A dancer moves counterclockwise at a constant | vedclass

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(B) The dancer moves at a constant speed $v$ along the path. In the straight-line segments $PQ$ and $RS$,the direction of motion does not change,so th

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(B) The dancer moves at a constant speed $v$ along the path. In the straight-line segments $PQ$ and $RS$,the direction of motion does not change,so the velocity vector remains constant. Therefore,the acceleration $a = \frac{dv}{dt} = 0$ in these segments. In the semicircular segments $QR$ and $SP$,the dancer is moving along a curved path with a constant speed $v$. This results in a centripetal acceleration with a magnitude $a = \frac{v^2}{r}$,where $r$ is the radius of the semicircle. Since $v$ and $r$ are constant,the magnitude of the acceleration is constant and non-zero during these segments. Thus,the acceleration is zero during $PQ$ and $RS$,and constant non-zero during $QR$ and $SP$. This corresponds to the graph in option $B$.

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